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Quiz Chapter 4: Indices, Surds and Logarithms

10 questions · Form 4 Additional Mathematics Bab 4: Indices, Surds and Logarithms

Question 1 of 10Score: 0

Use the change of base formula to evaluate log₄ 64.

Full Question List & Answer Key

Prefer reading to quizzing? All 10 questions are listed below with the answer and explanation under each one.

1. Use the change of base formula to evaluate log₄ 64.

  1. 3
  2. 4
  3. 16
  4. 2
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Answer: A

log₄ 64 = log₁₀ 64 / log₁₀ 4 = log₁₀ (4³) / log₁₀ 4 = 3 log₁₀ 4 / log₁₀ 4 = 3.

2. Express 12 + √3 with a rational denominator.

  1. 2 - √3
  2. 2 + √3
  3. -2 + √3
  4. √3 - 2
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Answer: A

Multiply by conjugate (2 - √3): 1 × (2 - √3)(2 + √3)(2 - √3) = 2 - √34 - 3 = 2 - √3.

3. Simplify √20 + √45 - √5.

  1. 4√5
  2. 5√5
  3. 3√5
  4. 2√5
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Answer: A

Simplify each surd: √20 = 2√5, √45 = 3√5. Then 2√5 + 3√5 - 1√5 = (2 + 3 - 1)√5 = 4√5.

4. Solve the equation 22x + 1) - 5(2^x) + 2 = 0 for x.

  1. x = -1 or x = 1
  2. x = 0 or x = 2
  3. x = -1 or x = 0
  4. x = 1 or x = 2
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Answer: A

Rewrite as 2(2^x)² - 5(2^x) + 2 = 0. Let u = 2^x: 2u² - 5u + 2 = 0 => (2u - 1)(u - 2) = 0 => u = 12 or u = 2. Thus 2^x = 2⁻¹ => x = -1, and 2^x = 2¹ => x = 1.

5. Solve 5^x = 20 correct to 3 decimal places.

  1. 1.861
  2. 1.301
  3. 2.000
  4. 1.431
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Answer: A

Take log₁₀ on both sides: log₁₀ (5^x) = log₁₀ 20 => x log₁₀ 5 = log₁₀ 20 => x = log₁₀ 20 / log₁₀ 5 ≈ 1.301030.69897 ≈ 1.861.

6. Solve the logarithmic equation log₂ (x + 2) + log₂ (x - 2) = 3.

  1. x = 2√3
  2. x = √12
  3. x = 4
  4. x = -2√3 or x = 2√3
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Answer: A

Combine logs: log₂ [(x+2)(x-2)] = 3 => log₂ (x² - 4) = 3 => x² - 4 = 2³ = 8 => x² = 12 => x = √12 = 2√3. (Reject x = -2√3 since log domain x > 2).

7. Which of the following numbers is an example of a surd?

  1. √16
  2. 94
  3. √7
  4. ∛27
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Answer: C

√16 = 4, √(94) = 32, and ∛27 = 3 are all rational numbers. √7 is irrational and cannot be expressed as a ratio of integers, making it a surd.

8. Find the conjugate surd of (3 - √5) and simplify their product.

  1. Conjugate is (3 + √5), product is 4
  2. Conjugate is (-3 - √5), product is 4
  3. Conjugate is (3 + √5), product is 14
  4. Conjugate is (-3 + √5), product is -4
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Answer: A

The conjugate of (3 - √5) is (3 + √5). Product: (3 - √5)(3 + √5) = 3² - (√5)² = 9 - 5 = 4.

9. Given log₂ y = 3 - 2 log₂ x, express y in terms of x.

  1. y = 8x²
  2. y = 6x²
  3. y = 8x²
  4. y = 2³ - x²
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Answer: A

log₂ y + 2 log₂ x = 3 => log₂ y + log₂ (x²) = 3 => log₂ (y x²) = 3 => y x² = 2³ = 8 => y = 8x².

10. If 3^(x + 2) = 27^(x - 1), find the value of x.

  1. x = 52
  2. x = 32
  3. x = 2
  4. x = 3
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Answer: A

Express base as 3: 3^(x + 2) = (3³)^(x - 1) => 3^(x + 2) = 33x - 3) => x + 2 = 3x - 3 => 2x = 5 => x = 52.

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